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11x^2+7x-30=0
a = 11; b = 7; c = -30;
Δ = b2-4ac
Δ = 72-4·11·(-30)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-37}{2*11}=\frac{-44}{22} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+37}{2*11}=\frac{30}{22} =1+4/11 $
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